Question

find the differential coefficient of the following :-

i) (x-1)(2x+5)
ii) 1/2x+1
iii) 3x+4/4x+5
iv) x^2/x^3+1

Answer 1

Heya !!!



(1) ( X -1) ( 2X +5)


=> X ( 2X +5) -1 ( 2X +5)



=> 2X² + 5X - 2X - 5


=> 2X² + 3X -5


Here,



Coefficient of X² is 2



Coefficient of X is 3 and constant term is -5.




(2) 1/2X +1



Coefficient of X is 2




(3) 3X +4 / 4X +5




=> 3X+4/ 4X +5 × 4X -5/ 4X -5



=> ( 3X +4) ( 4X -5) / ( 4X +5) ( 4X -5)




=> 3X ( 4X -5) +4 ( 4X -4) / (4X)² - (5)²



=> 12X² - 15X + 16X - 16 / 16X² -25



=> 12X² + X - 16 = 0


Here,



Coefficient of X² is 12


Coefficient of X is 1 and constant term is -16

Answer 2

Answer:

Step-by-step explanation:(1) 4x+3

(2)-2/(2x+1)²

(3) -1/(4x+5)²

(4) 2x-x⁴/(x³+1)²