Question

Find the differential equation if y=A sin x+B cos x​

Answer 1

Answer:

dy/dx=Acosx-Bsinx

Step-by-step explanation:

diff w. r. t x dy/dx= Acosx-Bsinx diff once again w. r. t x, then d2y/dx square= -Asinx-Bcosx ,taking(-) sign common out then,= - (Asinx+Bcosx) = -y,therefore d2y/dx square= -y,hence our differential eqn is d2y/dxsqure +y=0