Find the differential equation whose solution is y=acos(x+2)
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Answer:
dx
dy
+ytan(x+3)=0
y=Acos(x+3) (i)
dx
dy
=−Asin(x+3) ..(ii)
by (ii)÷ (i)
y
dx
dy
=−tan(x+3)
dx
dy
+ytan(x+3)=0
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