Question

find the differential equations of y=Acosx+sinx

Answer 1

Answer:

dy/dx = Cosx - Asinx

Step-by-step explanation:

find the differential equations of y=Acosx+sinx

y  = Acosx  + sinx

differentiation of cosx = - sinx  

& differentiation of Sinx = Cosx

=> dy/dx = d(Acosx)/dx  + d(sinx)/dx

=> dy/dx = Ad(cosx)/dx  + d(sinx)/dx

=> dy/dx = -ASinx  + Cosx

=> dy/dx = Cosx - Asinx