find the differentiation of log x÷x
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⭐《ANSWER》
↪Actually welcome to the concept of the DERIVATIVES
↪Basically here we are going to use the , U/V Rule ,
↪so we get as ,
↪d/dx ( U/V) = VdU - UdV ÷ V^2
↪so here we get as
↪dy/dx = (logx (1) - x * 1/x ) ÷ x^2
↪so here we get as ,
〽⭐dy/dx =( log x - 1 ) ÷ x^2
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