find the differentiation of y= sin 2x cos 2x
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1
Answer:
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Answered by
0
Answer:
We have sin
2
x+cos
2
y=1
Differentiating both sides w.r.t. x, we obtain
dx
d
(sin
2
x+cos
2
y)=
dx
d
(1)
⇒2sinx.
dx
d
(sinx)+2cosy.
dx
d
(cosy)=0
⇒2sinxcosx+2cosy(−siny).
dx
dy
=0
⇒sin2x−sin2y
dx
dy
=0
∴
dx
dy
=
sin2y
sin2x
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