find the differnce between the simple interest and the compound interest on rs5000 for 2yrs at 9%per annum
Answers
Step-by-step explanation:
givan:
P= 5000
I= 9%
T= 2
sol:
SI = PTR/100
=5000×2×9/100
=50×2×9
=900. A=5000+900=5900
AMOUNT OF CI =P(1+R/100)2
=5000(1+9/100)2
=5000×109/100×109/100
=109×109/2
=11881/2
=5940.5
DIFFERENCE= 5940.5-5900
=40.50 ₹
Answer:
p=5000
t=2
r=9% p.a
1) Simple Interest = prt/100
==> 5000*2*9/100 = 10000*9/100
==> zeros get cut
So 100*9 = 900
Hence SI = 900 rs
2) compound Interest
==> CI's amount = p(1+r/100)^t
==> 5000(1+9/100)^2 [here 9/100 is a fraction so considre it that way.]
==> First add 1 + 9/100
LCM of 1 and 100 is 100 so, 5000(100/100 + 9/100) [ here '100/100' and ' 9/100' are both fraction please don't divide it and consider it as fraction ]
==>5000(109/100)^2
==>5000(11881/10000)
=11881*5/10 = 59405/10
=5940.5
ci=5940.5-5000
=940.5
Difference=900-940.5=40.5