Question

find the diffrentiation of e^x^x




i will mark as brainliest and its for hundred points

Answer 1

i am not sure, but hope this helps!!

Answer 2

hi mate,

solution:

d/dx[e^x^x]

=e^x^x • d/dx[x^x]

=e^x^x • x^x • d/dx[ln(x)^x]

=e^x^x • x^x • (d/dx[x] • ln(x)+x • d/dx [ln(x)] )

=e^x^x • x^x • (1 • ln(+x⋅1/x)

=x^x • e^x^x • (ln(x)+1)

i hope it helps you.