Math, asked by donlucky716, 7 months ago

Find the digit in the ones place in the
cubes of the following numbers.
(1) 12 (ii) 23 (iii) 34
(iv) 65 (v) 78 (vi) 89​

Answers

Answered by Anonymous
8

Answer:

1. 8

2. 7

3. 4

4. 5

5. 2

6. 9

Hope it helps

Answered by Rameshjangid
1

Final Answer:

The digits which are available in one's place in the cubes of the numbers (1) 12 (ii) 23 (iii) 34 (iv) 65 (v) 78 (vi) 89​ are 8, 7, 4, 5, 2, and 9 respectively

Given:

The numbers given are the following (1) 12 (ii) 23 (iii) 34 (iv) 65 (v) 78 (vi) 89​.

To Find:

The digits which are in one's place in the cubes of the above numbers

Explanation:

When a number is multiplied by itself twice, the resulting number becomes a cube.

The digit in one's place in the cubes of any number is found by finding the cube of the unit place's digit of the number only.

Step 1 of 3

The digits which are in one's place in the numbers (1) 12 (ii) 23 (iii) 34 (iv) 65 (v) 78 (vi) 89​ are 2, 3, 4, 5, 8, and 9 respectively.

Step 2 of 3

The cubes of the numbers 2, 3, 4, 5, 8, and 9​ are 8, 27, 64, 125, 512, and 729 respectively.

Step 3 of 3

By observation, the unit place's digits in the cubes of the referred numbers are 8, 7, 4, 5, 2, and 9 respectively.

The required digits which exist in one's place in the cubes of the numbers (1) 12 (ii) 23 (iii) 34 (iv) 65 (v) 78 (vi) 89​ are 8, 7, 4, 5, 2, and 9 respectively.

Know more from the following links.

https://brainly.in/question/54136775

https://brainly.in/question/51610716

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