Find the digit in unit's place
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Answer:
viii) the unit digit is 8
ix) the unit digit is 9
Step-by-step explanation:
viii) 8^2009
the unit place is 8
as we now that
- (....8)^4k→ unit digit is 6
- (....8)^4k+1→ unit digit is 8
- (....8)^4k+2→ unit digit is 4
- (....8)^4k+3→ unit digit is 2
where (...8) is any number with 8 as it's unit place...and k is constant....
In this case, 8^2009 can be written as 8^2008+1= 8^4x502+1
so, 8^4x502+1 is in the form(....8)^4k+1
therefore, the unit digit will be 8
ix) 9^1999
the unit place is 9
as we know that,
- (....9)^odd power→ unit digit is 9
- (....9)^even power→ unit digit is 1
in this case, 9^1999
1999 is odd....
so, the unit digit will be 9
since, (....9)^odd power→ unit digit is 9...
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Answered by
2
Answer:
viii)The unit place is 8
ix) the unit place is 9
hope it helps you
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