Question

Find the digital at the unit place in the number 2019^2020 + 2020^2019​

Answer 1

Answer:

${2019}^{2020} + {2020}^{2019}$

just imagine the number 2019=odd number and 2020=

even number.

$= ({ - 1})^{2} + {1}^{ -2}$

$= 1 + 1 = 2 \: is \: the \: answer \: of \: this \: question$