Question

find the digits p and q if p7 q6 is divisible by 24​

Answer 1

Answer:

P 7 Q 6 = 2736

Step-by-step explanation:

P 7 Q 6 is divisible by 24 so,  divisible by 1 , 2 , 3 , 4, 6 , 8 .12 , 24 ( factors of 24 )

A ) SO , it is divisible by 3 ,

sum of P + 7 + Q + 6 is divisible by 3

so , P + Q + 13 is divisible by 3 - i

B ) ALSO ,  it is divisible by 4 ,

q  6 is divisible by 4 i.e. Q should be 1 / 3 / 5 / 7 / 9 -  ii

C )  AND , it is divisible by 8 ,

7 Q  6 is divisible by 8 . i.e. Q should be 3 / 7 - iii

Taking minimum number , Q should be 3 .

AND by statement i , p + q + 13 is divisible by 3

P+ 3 + 13 = P + 16 is divisible by 3 ,

By hit and trial method , P = 2

Hence the number is 2736 .