Question

find the digonal of a squre whose digonal is 10 cm.​

Answer 1

The side of square is 10 cm

In right angled △ABD

AB2+AD2=BD2 [according to Pythagoras theorem]

(10)2+(10)2=BD2$

100+100=BD2

BD2=200

BD=10 root 2cm

∴ Diagonal of square =10 root 2cm.

Answer 2

Answer:

10$\sqrt{2}$

Step-by-step explanation:

Applying pythagoras theorem:

Diagonal=h

b=10 cm

p=10 cm

h=$\sqrt{b^{2}+p^{2} }$

=$\sqrt{10^{2}+10^{2} }$

=$\sqrt{200}$

=10$\sqrt{2}$