Question

find the dimension bracket in natural number and hence the perimeter of the value of rectangle having area as 20 square CM​

Answer 1

Step-by-step explanation:

20= a x b where a is length and b be breadth of a rectangle

a and b can be any number so that a x b =20 but since a,b belong to Natural number set so a = 4 and b = 5 .

Now perimeter of the rectangle = 2(4+5) = 18cm