Find the dimension of a,b,c and d
When the distance covered by a particle in time ,t, is going by
X=a+bt+ct^2+dt
Please help
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In this case.,
a = X = (a) = (L)
bt = X
b = X/t = (b) =(L) /(T)
ct^2 = X
c = X/t^2 = (c) = (L) /(T^2)
dt = X
d = X/t = (L) /(T).
a = X = (a) = (L)
bt = X
b = X/t = (b) =(L) /(T)
ct^2 = X
c = X/t^2 = (c) = (L) /(T^2)
dt = X
d = X/t = (L) /(T).
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