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Find the dimension of A, B, C, D and E in X=A+Bt+Ct2+ (Dt3/E+t) where X is displacement and it's time

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**Explanation:**

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**The dimensions of A,B, C, D and E are ****, ****, ****, **** and **** respectively.**

**Given,**

Equation:.

X-displacement and t-time.

**To find,**

the dimension of A, B, C, D and E.

**Solution:**

- The principle that will be used here is known as "Principle of homogeneity of dimensions".
- It states that the dimensions of all the terms in an equation must be equal.
- Simply, it states that we add or subtract similar physical quantities.

Dimensions of E=Dimensions of t

**Dimensions of E=[T].**

Dimensions of A=Dimensions of X

**Dimensions of A=[L].**

Dimensions of Bt=Dimensions of A

Dimensions of B=Dimensions of A/Dimensions of t

Dimensions of B=[L]/[T]

**Dimensions of B=****.**

Dimensions of =Dimensions of A

Dimensions of C=Dimensions of A/Dimensions of

Dimensions of C=

**Dimensions of C=****.**

Dimensions of =Dimensions of A

Dimensions of D={Dimensions of A x Dimensions of (E+t)}/Dimensions of

Dimensions of D=

**Dimensions of D=****.**

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