Question

Find the dimension of a/b in the equation P = a - t^2 where, P is pressure, x is distance and t is time.. ​

Answer 1

Hey , refer to attachment plse..

Hope it helps!!

Answer 2

Q. Find the dimension of a/b in the equation P = a - t^2 where, P is pressure, x is distance and t is time.

ans :-$\frac{a}{b} = ( {m}^{2} {l}^{ - 2} {t}^{ - 6} )$

Explanation:-

Given :-

$p = pressure = (m {l}^{ - 1} {t}^{ - 2} )$

$x = distance = (l)$

$t = time = (t)$

By using the principal of homeginity

$p = a$

$a = (m {l}^{ - } {t}^{ - 2} )$

$p = \frac{ {t}^{2} }{bx}$

$(m {l}^{ - 1} {t}^{ - 2} ) = \frac{ {t}^{2} }{b(l)}$

$b = \frac{ {t}^{2} }{(m {t}^{ - 2}) }$

$b = ( {m}^{ - 1} {t}^{4} )$

$\frac{a}{b} = \frac{(m {l}^{ - 1} {t}^{ - 2}) }{( {m}^{ - 1} {t}^{4}) }$

$\frac{a}{b} = ( {m}^{2} {l}^{ - 2} {t}^{ - 6} )$