Find the dimension of a/b in the equation p=b-x^2/at where p is pressure,x is distance and t is time.
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Question :
An object travels 20m in 4s and then other 20m in 10s . What is the average speed of the object ?
Solution :
As per the question we have two cases so let's assume each as Case 1 and Case 2 respectively !
Case 1 :
Distance Covered : 20m
Time taken : 4 sec
Speed : Distance / time
: 20 / 4
: 5 m / sec
Case 2 :
Distance Covered : 20 m
Time taken : 10 sec
Speed : Distance / time
: 20 / 10
: 2 m / sec
huge average speed = total distance total time
averagespeed=totaltimetotaldistance
= \5 + 2 4 + 10=4+105+2
= 7 40 = 0.175=407=0.175
Hence , the average speed of the object is 0.175 m / sec !!
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