find the dimension of power force permittivity and vacuum
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Answered by
5
PEMITTIVITY= (CHARGE)^2 /(FORCE)*(DISTANCE)^2
=[TA]^2 / [MLT^ -2] [L]^2
=[TA]^2 / [ML^3T^ -2]
=[M^ -1 L^ -3 T^2+2 A^2]
= [M^ -1 l^ -3 T^4 A^2]
.
=[TA]^2 / [MLT^ -2] [L]^2
=[TA]^2 / [ML^3T^ -2]
=[M^ -1 L^ -3 T^2+2 A^2]
= [M^ -1 l^ -3 T^4 A^2]
.
Answered by
1
PEMITTIVITY= (CHARGE)^2 /(FORCE)*(DISTANCE)^2
=[TA]^2 / [MLT^ -2] [L]^2
=[TA]^2 / [ML^3T^ -2]
=[M^ -1 L^ -3 T^2+2 A^2]
= [M^ -1 l^ -3 T^4 A^2]
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