Find the dimension of rectangle when its length is 20 m more than its width. if its width is reduced by 20 m and increased by 100 m then the perimeter will be twice the perimeter of the original onen
Answers
Answered by
6
Answer:
x=80
Step-by-step explanation:
Original
width=x;length=20+x
perimeter=2(l+b)
2(20+x+x)
2(20+2x)
40+4x
Altered
width=x-20+100
length=20+x
perimeter=2(20+x+x-20+100)
2(2x+100)
4x+400
ATQ=2(40+4x)=4x+400
80+8x=4x+400
8x-4x=400-80
4x=320
x=320/4
x=80
so, width=80
length=20+x
20+80=100
Answered by
0
Answer:
here is your answer
hope it helps
Attachments:
Similar questions