Question

Find the dimension of rectangle when its length is 20 m more than its width. if its width is reduced by 20 m and increased by 100 m then the perimeter will be twice the perimeter of the original onen

Answer 1

Answer:

x=80

Step-by-step explanation:

Original

width=x;length=20+x

perimeter=2(l+b)

2(20+x+x)

2(20+2x)

40+4x

Altered

width=x-20+100

length=20+x

perimeter=2(20+x+x-20+100)

2(2x+100)

4x+400

ATQ=2(40+4x)=4x+400

80+8x=4x+400

8x-4x=400-80

4x=320

x=320/4

x=80

so, width=80

length=20+x

20+80=100

Answer 2

Answer:

here is your answer

hope it helps