find the dimension of s=at+bt^2
Answers
Explanation:
let us assume v represents velocity and t represents time in given expression then we may find dimensions of a & b as following
L.H.S=v
=[L][T^(-1)]
R.H.S=at+bt^2
[at]=[bt^2](since only quantity of same dimensions are additive.)
[bt^2]=[bT^2]
since LHS should be equal to RHS
so
[bT^2]=[LT^(-1)]
b=LT^(-3)
so dimension of b will be [LT^(-3)]
If v represents velocity and the represents time then
[v] = [at] = [bt²]
[LT^-1] = [bT²]
[b] = [LT^-3]
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