Physics, asked by MathCracker, 6 hours ago

Find the dimension of :
\varepsilon_0

Hint :-

Formula : 1/4πF × q1•q2/r²​

Answers

Answered by amiyakardong5
0

Answer:

 { {5}^{?} }^{?} 311)xy6()7163(9) + 16 -  {?}^{2} 13 =

Answered by vikkiain
1

Answer:

F/m

Explanation:

[F]=[1/4π]x[q1.q2/]

or,

N=[]xC.C/

or,

[]=Nm²/C² = (Nm/C)(m/C) = (J/C)(m/C)

= Vm/C = (V/C)/m = F/m.

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