find the dimension of the constant a,b,c and d. in the relation v= √ab + b + c/d+t where v is velocity and t is time..
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We will use concept that only quantities with same dimension cn be added and can be equated.
Explanation:
Dimension of velocity is [L]¹[T]-1
So dimension of B will also be same [L]¹[T]-1
Dimension of √ab will also be same
√a[L]¹[T]-1 =[L]¹[T]-1
a[L]¹[T]-1 = [L]²[T]-2
So dimensions of a=[L]¹[T]-1
Now for dimension of c and d
Dimension of d will be same as time [T]¹
dimension [c]¹[d]-1 =[L]1[T]-1
so dimension of c is [L]¹
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