Question

find the dimension of the rectangular piece of land if its length is 5 metres more than 4 times its width and the perimeter is 66m​

Answer 1

$\mapsto\sf\green{Given:-}$

$\green \mapsto \sf{Length \: is \: 5 \: metres \: more \: than \: 4 \: times \: its \: width}$

$\green\mapsto\sf{Perimeter \: is \: 66m}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \:$

$\mapsto\sf \green{According \: to \: given \: statement:}$

Length becomes 4 times means 4x and plus 5 metres means + 5 metres so the whole equation becomes Length = (4x + 5) metres

And,

Breadth = x metres

$\: \: \: \: \: \: \: \: \: \: \: \: \: \:$

$\mapsto\sf \green{According \: to \: question:-}$

We know that

$\green\mapsto\sf{Perimeter = 2(Length + Breadth) }$

$\green \mapsto\sf{ 66 =2 (4x + 5 + x)}$

$\green \mapsto\sf{ 66 =2 (5x + 5)}$

$\green \mapsto\sf{ 66 =10x + 10}$

$\green \mapsto\sf{ 66 - 10 =10x }$

$\green \mapsto\sf{ 56 =10x }$

$\green \mapsto\sf{ \frac{56}{10} =x }$

$\mapsto\sf \green{ 5.6 =x }$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \:$

Now find Length

$\green \mapsto\sf{ 4x + 5}$

$\green \mapsto\sf{ 4 \times 5.6 + 5}$

$\green \mapsto\sf{ 22.4 + 5}$

$\green \mapsto\sf{ 27.4}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \:$

$\mapsto\sf \green{ length \: = \: 27.4m}$

$\mapsto\sf \green{ breadth \: = \: 5.6m}$

Answer 2

please scroll

hope it's helpful