Question

Find the dimension s of a and b given that where p is power and x is distance

Answer 1

$\: ANSWER</p><p></p><p>Given P=atb−x2</p><p>⇒Pat=b−x2</p><p>Implies both b and x^2 should have same units.</p><p>We know that [x2]=L2</p><p>Hence, [b]=L2</p><p>Similarly, [Pat]=[x2]=L2</p><p>[a]=[Pt]L2=(ML2T−3)(T)L2=M−1L0T2</p><p></p><p> \\ \\ \\ \\ \\ \\ hope \: it \: helps$

ANSWER

Given P=

at

b−x

2

⇒Pat=b−x

2

Implies both b and x^2 should have same units.

We know that [x

2

]=L

2

Hence, [b]=L

2

Similarly, [Pat]=[x

2

]=L

2

[a]=

[Pt]

L

2

=

(ML

2

T

−3

)(T)

L

2

=M

−1

L

0

T

2