Question

Find the dimensional correctness of formula T=2π√I/mgl

Answer 1

Answer:

Dimensional formula of T=[T]

D.F of l=[L]

D.F of g(acceleration due to gravity)=[LT^-2]

Now equating both sides using given formula

[T]=√[L]/√[LT^-2]

L will be cancel out

so:

[T]=√1/[T^-2]

[T]=√[T²]

[T]²=[T]²

L.H.S=R.H.S