Question

find the dimensional foemula of the 'A universal constant of gravitation(G)? ​

Answer 1

Answer:

, G = [M1 L1 T-2] × [L]2 × [M]-2 = [M-1 L3 T-2]. Therefore, the gravitational constant is dimensionally represented as M-1 L3 T-2.

Explanation:

I thik ok