Question

Find the dimensional of a÷b in the relation: F=ax+bt² , where F is force , x is distance ,and t is time

Answer 1

Answer:

f = a√x + bt2, where f = (M L T −2(, x = (L) and t = (T).

f = a√x = bt2

f = a√x

(M L T −2) = (a L½)

= (a) = (M L½ T −2)

F = (bt2)

(M L T −2) = (b T2)

= (b) = (M L T−4)

(a)/(b) = (M L½ T −2)/(M L T−4) = (M0 L−½ T2)

So, (a/b) = (M0 L−½ T2)

Answer 2

Answer:

I know only Hindi

Explanation:

so the question have any answer