Find the dimensions and units of epsilon_0
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Hey mate,
According to Coulomb's Law:
F=(1/4πε₀)q1q2/r²
ε₀=(1/4πF) q1q2/r²
Dimension formula of F=M¹L¹T⁻²
Charge =q=IXT=AxT¹ where A= electric current
ε₀=(1/M¹L¹T⁻²)(AT¹xAT¹)/L²
ε₀=M⁻¹L⁻³T⁴A²
∴ Dimensional Formula of Epsilon naught= M⁻¹L⁻³T⁴A²
Epsilon Naught Unit: Farad per meter(in SI)
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The unit and dimension as given below:
- The unit of epsilon is ∈=c²/Nm²
- Where c is charge q= current×time=(A)×(T)=AT
- Now calculate the dimension of force(N)= mass×acceleration
- Acceleration=LT⁻²
- Therefore dimension of force ML³T⁻²
- The dimension of epsilon is c²/Nm²
- (AT)²/ML³T⁻²
- That is [ML⁻³T⁴A]
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