Question

find the dimensions in the relation p=b-xsquare upon a t where x is distance p is pressure t is time
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Answer 1

Explanation:

P = b-x^2/at

x = separate =[L]

as the govern of documentation

measurement of b will be equivalent to measurement of [x^2]

Measurement of b = [L2]

P.at = b-x^2

As the measurement of Power is [ML2T-3]

Put in the condition

[ML2T-3] [a][T] = [L2]

[a] = [M-1 T2] .