Find the dimensions of a&b in the given relation P=b-x2/at
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Answer:
[a] = [M-1 T2] .
Explanation:
Given information
P = b-x^2/at
x = separate =[L]
as the govern of documentation
measurement of b will be equivalent to measurement of [x^2]
Measurement of b = [L2]
P.at = b-x^2
As the measurement of Power is [ML2T-3]
Put in the condition
[ML2T-3] [a][T] = [L2]
[a] = [M-1 T2] .
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