Question

find the dimensions of a and b in p =b-x²/at where p is power, x is distance and t is time.

Answer 1

p =b-x²/at

P = V X I

V = Work done/Charge

I = Charge/Time

[V] = [MT²]

[I] = [AT⁻¹]

[P] = [MT²] [AT⁻¹] = [MAT]

Now,

[x²] = [b]

[L²] = [b]

Putting in equation,

[MAT] = [L²] / [a] [T]

[a] = [M⁻¹A⁻¹L²T⁻²]