find the dimensions of a×b from P=b-xat 2/at
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Answer:
Answer
Correct option is
B
[M
−1
L
0
T
2
],[M
0
L
2
T
0
]
Dimensions of Power: P−ML
2
T
−3
Since the given expression is dimensionally correct, each term of the expression must have same dimensions as that of power.
Therefore,
[a][t]
[x
2
]
=
[a]T
L
2
=ML
2
T
−3
⇒[a]−M
−1
L
0
T
2
[a][t]
[b]
=
(M
−1
L
0
T
2
)(T)
[b]
=ML
2
T
−3
⇒[b]−L
2
Hence, Option A is correct.
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