Find the dimensions of a×b in the equation E=b-x2/at where E is tye the energy,x is distance and t is time
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Answer:
E = ( b -x²) /at
= ( b/at - x²/at)
where E = energy
t = time
x = displacement.
so,
dimension of E = dimension of { b/at }
b/at = E
b/a = Et
dimension of {a/b} = 1/Et = 1/[ ML²T-²][ T]
= [ M-¹ L-²T]
I hope it helps you
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