Find the dimensions of [a/b] in the equation P = a-t^2/ b-c Where P is pressure, x is distance and t is time.
Answers
Answered by
6
P = a − t2/bx = a − (t2/b)x = a − t2 x/b
P is pressure, x is distance and t is time.
[P] = [a] ⇒ [a] = [M L−1T −2]
[P] = [ t2 x/b] ⇒ [b] = [ t2 x/P]
⇒ [b] = [T2 . L. M−1 L T 2]
= [M−1 L2 T 4]
[a/b] = [M L−1T −2]/[M−1 L2 T 4] = [M2 L−3 T −6]
P is pressure, x is distance and t is time.
[P] = [a] ⇒ [a] = [M L−1T −2]
[P] = [ t2 x/b] ⇒ [b] = [ t2 x/P]
⇒ [b] = [T2 . L. M−1 L T 2]
= [M−1 L2 T 4]
[a/b] = [M L−1T −2]/[M−1 L2 T 4] = [M2 L−3 T −6]
Similar questions