Question

Find the dimensions of a*b in the relation P=(b-x2)/at. Where P is power,x is distance and t is time.

Answer 1

P= b-x²/at

P=b/at-x²/at

According to principle of homogeneity of dimensions

P=x²/at

a=x²/Pt

a=[L²] /[L²M¹T-³] [T¹]

a=[L²] /[L²M¹ T-²]

a=[M-¹ T²]

P=b/at

b=P×a×t

b=[L²M¹T-³] [M-¹ T²] [T¹]

b=[L²M¹T-³] [M-¹ T ³]

b=[L²]

I hope this helps ( ╹▽╹ )