Find the dimensions of (a) electric field E, (b) magnetic field B and (c) magnetic permeability μ₀ .
Concept of Physics - 1 , HC VERMA , Chapter "Introduction to Physics".
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(a) We know that the formula of Electric field E is :-
E= F/q
Now changing into dimensions.
E= MLT⁻² / I.T
E= MLT⁻³ I⁻¹
Hence the dimensional formula of Electric field is MLT⁻³I⁻¹ .
(B) We know that the formula of Magnetic field B is :-
Magnetic field, B=
Now changing into dimensions.
B = MLT⁻² / [IT] [LT⁻¹]
B= MT⁻² I⁻¹
Hence the dimensional formula of Magnetic Field B is MT⁻²I⁻¹ .
(C) We know that the formula of Magnetic permeability is :-
μ₀ = (B× 2πa) / I
μ₀ = [MT⁻²I⁻¹ × L] / I
μ₀ = MLT⁻² I⁻¹
Hence the dimensional formula of Magnetic permeability is MLT⁻² I⁻¹ .
Hope it helps.
(a) We know that the formula of Electric field E is :-
E= F/q
Now changing into dimensions.
E= MLT⁻² / I.T
E= MLT⁻³ I⁻¹
Hence the dimensional formula of Electric field is MLT⁻³I⁻¹ .
(B) We know that the formula of Magnetic field B is :-
Magnetic field, B=
Now changing into dimensions.
B = MLT⁻² / [IT] [LT⁻¹]
B= MT⁻² I⁻¹
Hence the dimensional formula of Magnetic Field B is MT⁻²I⁻¹ .
(C) We know that the formula of Magnetic permeability is :-
μ₀ = (B× 2πa) / I
μ₀ = [MT⁻²I⁻¹ × L] / I
μ₀ = MLT⁻² I⁻¹
Hence the dimensional formula of Magnetic permeability is MLT⁻² I⁻¹ .
Hope it helps.
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