Find the dimensions of
(a) linear momentum,
(b) frequency and
(c) pressure.
Concept of Physics - 1 , HC VERMA , Chapter "Introduction to Physics".
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Hello Dear.
(a)
Formula of Linear Momentum is given by →
p = m × v
where, p = Linear momentum, m = mass and v = velocity.
Now, Dimension of Mass = M L⁰ T⁰
& Dimension of Velocity = M⁰L¹T⁻¹
∴ [p] = (M¹ × 1 × 1) × (1 × L¹ × T⁻¹)
[ ∵ a⁰ = 1]
⇒ [p] = M¹ L¹ T⁻¹
Hence, Dimension of the Linear Momentum is M¹L¹ T⁻¹.
______________________
(b) ∵ Frequency = 1/Time
∴ [f] = 1/T
⇒ [f] = T⁻¹
Hence, the Dimension of the Frequency is M⁰ L⁰ T⁻¹.
______________________
(c) ∵ Pressure = Force/Area
Dimension of Force = M¹ L¹ T⁻²
& Dimension of Area = M⁰ L² T⁰
= L²
∴ [P] = (M¹ L¹ T⁻²) ÷ (L²)
⇒ [P] = M¹ L⁻¹ T⁻²
Hope it helps.
(a)
Formula of Linear Momentum is given by →
p = m × v
where, p = Linear momentum, m = mass and v = velocity.
Now, Dimension of Mass = M L⁰ T⁰
& Dimension of Velocity = M⁰L¹T⁻¹
∴ [p] = (M¹ × 1 × 1) × (1 × L¹ × T⁻¹)
[ ∵ a⁰ = 1]
⇒ [p] = M¹ L¹ T⁻¹
Hence, Dimension of the Linear Momentum is M¹L¹ T⁻¹.
______________________
(b) ∵ Frequency = 1/Time
∴ [f] = 1/T
⇒ [f] = T⁻¹
Hence, the Dimension of the Frequency is M⁰ L⁰ T⁻¹.
______________________
(c) ∵ Pressure = Force/Area
Dimension of Force = M¹ L¹ T⁻²
& Dimension of Area = M⁰ L² T⁰
= L²
∴ [P] = (M¹ L¹ T⁻²) ÷ (L²)
⇒ [P] = M¹ L⁻¹ T⁻²
Hope it helps.
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