Question

Find the dimensions of a rectangle having perimeter 40 m, if it's length is 4 m less than twice its breadth.

c) l = 11 m. , b = 9 m


d) l = 14 m, b = 6 m


a) l = 17 m, b = 3 m


b) l= 12 m , b = 8 m​

Answer 1

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Answer 2

perimeter=40m

length=2x-4

breadth=x

perimeter=2(l+b)

2(2x-4+x)=40

2(3x-4)=40

6x-8=40

6x=40+8

6x=48

x=48/6

x=8m

so, breadth=8m

length=12m

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