Question

Find the dimensions of a rectangle if the length is 2ft, less than twice the width and the perimeter is 26ft.?

Answer 1

Answer:

Length of the rectangle = 8 ft

Breadth of the rectangle = 5 ft

Step-by-step explanation:

Let the length and breadth of the rectangle be 'l' and 'b' ft respectively.

Perimeter of rectangle = 2(l + b)

Given,

l = 2b - 2 ---(1)

Perimeter = 26

2(l + b) = 26 ---(2)

Substituting eq 1 in 2

2(2b - 2 + b) = 26

2(3b - 2) = 26

6b - 4 = 26

b = 30/6 = 5 ft

Substituting b = 5 in eq 1

l = 2 × 5 - 2 = 10 - 2 = 8 ft