Find the dimensions of a rectangle whose area is given by 25 2 – 35 + 12
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20x-14
Step-by-step explanation: Area of rectangle = 25x^2– 35x + 12
We know, area of rectangle = length × breadth
So, by factoring 25x^2– 35x + 12, the length and breadth can be obtained.
25x^2– 35x + 12 = 25x^2– 15x – 20x + 12
=> 25x^2– 35x + 12 = 5x(5x – 3) – 4(5x – 3)
=> 25x^2– 35x + 12 = (5x – 3)(5x – 4)
So, the length and breadth are (5x – 3)(5x – 4).
Now, perimeter = 2(length + breadth)
perimeter of the rectangle = 2[(5x – 3)+(5x – 4)]
= 2(5x – 3 + 5x – 4) = 2(10x – 7) = 20x – 14
Thus, the perimeter = 20x – 14
Thanks
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