Question

find the dimensions of a rectangle whose perimeter is 112 cm and breadth is 4 cm less than half its length​

Answer 1

Step-by-step explanation:

Assumption: Let the length of the rectangle be x cm.

Breadth = x/2 - 4 cm

Perimeter = 2 × (length + breadth)

=> 112 = 2 × {x + (x/2 - 4)}

=> 112 = 2 × [x + {(x - 8)/2}]

=> 112/2 = x + (x - 8)/2

=> 56 = {2x + (x - 8)}/2

=> 56 = (3x - 8)/2

=> 56 × 2 = 3x - 8

=> 112 + 8 = 3x

=> 120 = 3x

=> 40 = x

Length = x cm

= 40 cm

Breadth = x/2 - 4 cm

= 40/2 - 4 cm

= 20 - 4 cm

= 16 cm

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Answer 2

Answer:

find the dimensions of a rectangle whose perimeter is 112 cm and breadth is 4 cm less than half its length

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