Question

find the dimensions of a rectangle whose perimeter is 28metres an area is 40 square metres ​

Answer 1

Answer:

Let the length be 'l'.

Let the breadth be 'b'.

Step-by-step explanation:

perimeter=2(l+b)=28

area=lb=40

Then l+b=14,lb=40.

By solving above equations we get,

l=10m,b=4m

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Answer 2

Given,
Perimeter = 28 m
Area = 40 m^2
Solution,
P= 2( l+b)
28= 2(l+b)
28/2 = (l+b)
14 = (l+b)
Area = (l*b)
40 = (l*b)
(l-b)^2 = ( l+b)^2 - 4* l*b
(l-b)^2 = (14)^2 -4* 40
(l-b)^2 = (14)^2 - 160
(l-b)^2 = 196 -160
(l-b)^2 = 36
(l-b) = 6 m
(l+ b)+(l-b) = 14+6
l+ b+l-b = 20
2l =20
L= 20/2
L=10m
(l+ b)= 14
10+b=14
b= 14-10
b= 6 m