find the dimensions of a rectangle whose perimeter is 28 metres and whose area is 40 square metres
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Answered by
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Step-by-step explanation:
Given,
Perimeter of rectangle = 28
2(l+b)= 28
l + b = 14
l = 14-b .....(1)
Area = 40
l × b = 40
from equ...(1)
(14-b)×b=40
(14-b^)=40
b^-14b+40=0
b^ -4b -10b+40=0
b(b-4)-10(b-4) =0
b-4=0 b-10= 0
b=4 b = 10.
therefore, length of rectangle = 10
breath of rectangle = 4
Answered by
1
Given,
Perimeter of rectangle = 28
2(l+b)= 28
l + b = 14
l = 14-b .....(1)
Area = 40
l × b = 40
from equ...(1)
(14-b)×b=40
(14-b^)=40
b^-14b+40=0
b^ -4b -10b+40=0
b(b-4)-10(b-4) =0
b-4=0 b-10= 0
b=4 b = 10.
therefore, length of rectangle = 10
breath of rectangle = 4
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