Find the dimensions of a rectangle whose perimeter is 28 meters and whose area is 10
meton
S
The base of a triangle is 4cm longer than its altitude. Ir the area of the triangle
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first:
take perimeter,
2( l + b ) = 28
l + b = 14
b = 14 - l
second :
take area,
l × b = 10
( 14 - l ) ( l ) = 10
14l - l ^ 2 = 10
l ^ 2 + 14 l - 10 =0
factorise to get dimensions
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