Question

Find the dimensions of a rectangle whose perimeter is 28 meters and whose area is 40
square meters
​

Answer 1

Step-by-step explanation:

2(l+b)=28

l+b =14

l =14-b

lb =40

l =40/b

Therefore

14-b =40/b

14b-b²=40

b²-14b+40=0

b²-4b-10b+40=0

b(b-4)-10(b-4)=0

b-4=0, b=4 and b-10=0, b=10

If b=4,

l=14b=14-4=10

=40/4=10

Therefore b=4 and l=10

Answer 2

Question ⏬

Find the dimensions of a rectangle whose perimeter is 28 meters and whose area is 40

square meters.

Answer ⏬

Check out the attachment please.

#KEEPLEARNING

HOPE I AM CLEAR.

WARM REGARDS.

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