Question

Find the dimensions of a rectangle whose perimeter is 28 meters and whose area is 40square
meters.
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Answer 1

HEY BUDDY HERE IS YOUR ANSWER

Let the length of the rectangle be l and breadth be b

then,

        2(l + b) = 28

    => l + b = 14 .....................(i)

Then,

        l*b = 40

    => l = 40/b  ..........................(ii)

Putting (ii) in equation (i)

                  l + b = 14

              =>40/b + b = 14

              =>40 + b^2 = 14b

              =>b^2 - 14b + 40 = 0

Applying quadratic formula we find 2 values for b which are 10 or 4

Hence if the breadth comes to be 10 and 4 then the length is either 4 or 10

So the length and breadth can be either and 4 and 10 or 10 and 4

HOPE IT HELPS

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