Question

Find the dimensions of a rectangle whose perimeter is 28 meters and whose area is 40
square meters.​

Answer 1

Question ⏬

Find the dimensions of a rectangle whose perimeter is 28 meters and whose area is 40

square meters.

Answer ⏬

Check out the attachment please.

#KEEPLEARNING

HOPE I AM CLEAR.

WARM REGARDS.

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Answer 2

Hmm okay... no prblm

Perimeter of rectangle = 28

2 (l + b ) = 28

l + b = 14

l = 14 - b --- (i)

area = 40

l × b = 40

Now, From (i)...

( 14 -b ) × b = 40

(14 - b²) = 40

b² - 14b + 40 = 0

After splitting the zeroes, we will get,

(length) = 10(breadth) = 4

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