Question

find the dimensions of a rectangle with a perimeter of 54 metres,if its length is 3 metres more than twice its width. ​

Answer 1

Given :

• Perimeter = 54 m

• Length = 3 m more than twice its width / Breadth

To find :

• The Dimensions of a Rectangle

Formula To be used :

Perimeter of Rectangle = 2 ( length + breadth )

According to the question :

Let the Breadth / width of a Rectangle be ' x '

Length will be = 3 + 2x

Applying Formula :

⟹ 2 [ ( 3 + 2x ) + x ] = 54

⟹ 2 [ 3 + 3x ] = 54

⟹ [ 2 × 3 ] + [ 2 × 3x ] = 54

⟹ 6 + 6x = 54

⟹ 6x = 54 - 6

⟹ 6x = 48

⟹ x = 48 / 6

⟹ x = 8

We got :

➳ Breadth / Width = 8 m

➳ Length = 3 + 2x = 3 + ( 2 × 8 ) = 3 + 16 = 19 m

So, It's Done !!

Answer 2

Dimensions of rectangle means its length and breadth because it's 2D.

Step-by-step explanation:

Given,

Let breadth of the rectangle be x m = b

and length of the rectangle be (2x+ 3)m = l

We know,

Perimeter of rectangle= 2(l+b) units

A/Q

2( 2x+3+x)= 54

=> 2( 3x+3)=54

=>. 6x + 6 =54

=>. 6x=48

=>. x= 8

now, b=x= 8 m

l= 2(8)+3 =19 m

We know,

Area of a rectangle = l x b sq units

Area of the rectangle = 19 x 8 m²

= 152 m² .