Math, asked by mshehhi2002, 6 months ago

Find the dimensions of a rectangle with a perimeter of 54 meters, if its length is 3 meters less than twice its width.

Answers

Answered by soumya3363

0

Answer:

L=17 m

W=10m

Step-by-step explanation:

L=2w-3 m

P=2 (l+w)

54=2 (2w-3 + w)

54=2 (3w-3)

54=6w-6

54+6=6w

60=6w

w=10m

l=2w-3

=2×10-3

=20-3

=17m

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